28y^2-45y-13=0

Solution for 28y^2-45y-13=0 equation:

28y^2-45y-13=0

a = 28; b = -45; c = -13;
Δ = b2-4ac
Δ = -452-4·28·(-13)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-59}{2*28}=\frac{-14}{56}
=-1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+59}{2*28}=\frac{104}{56}
=1+6/7
$